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1-49xx

-16+xx

100rr-9

2006-12-13 03:23:31 · 14 answers · asked by Kamani S 1 in Science & Mathematics Mathematics

14 answers

1)1-49x^2
so(1+7x)(1+7x)
2)-16+x^2
x^2-16
(x+4)(x+4)
3)100r^2-9
(10r-3)(10r+3)

2006-12-13 03:34:40 · answer #1 · answered by Anonymous · 0 0

Question :
Calculate The Following Questions Below.?

1-49xx

-16+xx

100rr-9

Answer:

1-49xx=-xx49+1

-16+xx=-16+xx

100rr-9=-9+100rr

2006-12-14 18:10:08 · answer #2 · answered by yassine 1 · 0 0

1-49x^2=(1-7x)(1+7x)
-16+x^2=(x-4)(x+4)
100r^2-9=(10r+3)(10r-3)

the above are simple as we have to write the given in terms of
x^2-a^2=(x-a)(x+a)

2006-12-14 00:02:34 · answer #3 · answered by bubbly 2 · 0 0

1-49xx=1-49x^2 =(1-7x)(1+7x)
-16+xx=x^2-16 =(x-4)(x+4)
100rr-9=100r^2-9 =(10r-3)(10r+3)

2006-12-14 01:30:16 · answer #4 · answered by bhaskar 1 · 0 1

The answers given above are correct, but let me tell you, you have not actually given the question.
It could be factorizing as most of the people have done, or it could even be finding roots. But as you have given only the expressions, factorizing seems most appropriate. But next time, please try giving a complete idea about the question.

2006-12-13 20:22:47 · answer #5 · answered by nayanmange 4 · 0 0

Differences of squares, all of them!
1 - 49xx =
1² - (7x)² =
(1+7x)(1-7x)

You do the rest...

2006-12-13 03:37:21 · answer #6 · answered by Anonymous · 0 0

possibly you are mischievous(but not than me).I've got the answer just by a look at it.nevertheless the answers can be:
1)-2351
2)95/2 , 1151/2
if they sound correct reply me with yes or no then i'll proceed

2006-12-13 03:46:50 · answer #7 · answered by Anonymous · 0 0

(1-7x)(1+7x)

(x-4)(x+4)

(10r-3)(10r+3)

2006-12-13 04:14:10 · answer #8 · answered by george t 2 · 0 0

1-49xx
(1-7x)^2
(1-7x)(1+7x)

-16+xx
(-4+x)^2
(-4+x)(4+x)

100rr-9
(10r-9)^2
(10r+3)(10r-3)

2006-12-13 04:16:11 · answer #9 · answered by Saphira 3 · 0 0

1-49xx
(1-7x)^2
(1-7x)(1+7x)

-16+xx
(-4+x)^2
(-4+x)(4+x)

100rr-9
(10r-9)^2
(10r+3)(10r-3)

2006-12-13 16:26:08 · answer #10 · answered by arpita 5 · 0 0

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