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A car with a mass of 700 kg moves at 15 m/s. What braking force is needed to bring the care to a halt in 10 seconds?

2006-12-13 03:10:38 · 4 answers · asked by Girl 2 in Science & Mathematics Physics

4 answers

the ecceleration occurs
with deceleration = speed/time15/10 =-1.5 ms^-2

F= m deceleration = -1.5 *700 = -1500Newton

2006-12-13 03:14:09 · answer #1 · answered by maussy 7 · 0 0

V=u-at=15-at
0=15-a*10
a=15/10=3/2 m/seec^2

Now Force,F=mass*Acceleration=ma=700*3/2=350*3=1050 Newton Ans.

2006-12-13 04:35:34 · answer #2 · answered by aminnyus 2 · 0 0

v= u + at
a= -1.5m/second square
F=m x a
F= 700 x 1.5 = 1050 Newton

2006-12-13 03:20:24 · answer #3 · answered by siddhant b 2 · 0 0

1050 N. Maybe. Physics a little rusty.

2006-12-13 03:19:04 · answer #4 · answered by dumdum 2 · 0 0

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