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1: Solve and write the solution in interval notation:
2x - 4 < 4 or x + 5 ≤ 2 - 2x
(-∞, 3)
(-∞, 4)
(-∞, ∞)
(-1, 4)


2:
2x > -10 or x > 1
(-1, 5)
(-5, 1)
(-5, ∞)
(-∞, ∞)


3:
y < 3 or 3y + 4 > -5
(-∞, 3)
(-3, 3)
(-3, ∞)
(-∞, ∞)


4: Write the solution to the compound inequality in compact form, write the solution in interval notation, and describe the graph.
Write in compact form:
-5 < 3x + 4 < 19

3 < x < 23/3
-3 < x < 23/3
3 < x < 5
-3 < x < 5


5: Write the above solution in interval notation:
(3, 5)
(-∞, 5)
(-3, 5)
(-∞, ∞)


6: Describe the above graph.
the entire graph is shaded
open circle on 5, and shaded to the left
open circle on -3, and shaded to the right
open circle on -3, open circle on 5, and shaded in between

2006-12-13 02:05:55 · 4 answers · asked by me1026 1 in Science & Mathematics Mathematics

4 answers

TRASH IT. Don't need any of it in real life.

2006-12-13 02:14:07 · answer #1 · answered by ladie_eclipse 2 · 0 2

I'll help you with the first one. 2x - 4 < 4 or x + 5 ≤ 2 - 2x. Solve each one separately:

First one:
2x - 4 < 4 add 4 to both sides
2x < 8 divide by 2
x < 4

Second one:

x + 5 ≤ 2 - 2x add 2x to both sided
3x + 5 ≤ 2 subtract 5 from both sides
3x ≤ -3 divide by 3
x ≤ -1

So you now have x < 4 or x ≤ -1. This always true if x<4, so your answer is (-∞, 4).

2006-12-13 10:25:37 · answer #2 · answered by Anonymous · 0 0

1)
2x – 4 < 4
2x < 8
x < 4

x + 5 ≤ 2 - 2x
3x ≤ -3
x ≤ -1
Ans: (-∞, 4)

2)
2x > -10
x > -5
x > 1

Ans: (-5, ∞)

3)
3y + 4 > -5
3y > -9
y > -3
y < 3
Ans: (-3, 3)

4)
-5 < 3x + 4 < 19
-9 < 3x < 15
Ans: -3 < x < 5

5)
Ans: (-3, 5)

6)
Ans: open circle on -3, open circle on 5, and shaded in between

dudes...this isn't very difficult...please try to help next time instead of posting other messages

2006-12-13 10:22:54 · answer #3 · answered by Anonymous · 0 0

lol. i dont think any1 will spend time doing that

2006-12-13 10:13:21 · answer #4 · answered by John B 1 · 0 0

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