2006-12-12 21:39:00 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
It is like a sideways parabola with a vertex at (2,-2) and opens to the left. It is a thin parabola.
Plot points to make it easier.
2006-12-12 21:44:05 · answer #1 · answered by ? 4 · 0⤊ 1⤋
Yikes that's a bit hard...
You need to get the equation looking like
y = .............
so first you take the squared sign away by getting the square root of the x value. This gives
(y+2) = sqrt(-4(x-2))
Then you subtract 2 from y giving you
y = sqrt(-4(x-2)) - 2
Simplified slightly it becomes
y = sqrt(8-4x) - 2
When (8-4x) is negative y and thus the graph do not exist for that value of x
Hope that helps
2006-12-12 21:50:40 · answer #2 · answered by neotheonereally 2 · 0⤊ 0⤋
y^2+4y+4=-4x+8
-4x=y^2+4y-4
x=[(y-2)/2]^2
make a table of values
x 25/4 4 3/4 1 1/4 0 1/4
y -3 -2 -1 0 1 2 3
graph now
2006-12-12 21:53:31 · answer #3 · answered by raj 7 · 1⤊ 0⤋
(y+2)^2= -4(x-2)
y^2+4+4y= -4x+8
y^2+4x+4y-4=0
put values -3 to 3
u'll get a left facing parabula
2006-12-12 21:51:32 · answer #4 · answered by avanthi 2 · 1⤊ 0⤋
It is like a sideways parabola with a vertex at (2,-2) and opens to the left. It is a thin parabola.
Plot points to make it easier.
2006-12-12 21:47:42 · answer #5 · answered by MANSI R 2 · 0⤊ 1⤋
(y+2)^2 = -4(X-2)
(y+2)^2 = -4x + 8
y^2 + 2y + 4 = -4x + 8
y^2 + 2y -4 = -4x
x = -(y^2 +2y -4)/4
Put this formula into Excel, here are the results
xy
-19.0-10.0
-14.8-9.0
-11.0-8.0
-7.8-7.0
-5.0-6.0
-2.8-5.0
-1.0-4.0
0.3-3.0
1.0-2.0
1.3-1.0
1.00.0
0.31.0
-1.02.0
-2.83.0
-5.04.0
-7.85.0
-11.06.0
-14.87.0
-19.08.0
-23.89.0
-29.010.0
2006-12-12 21:49:01 · answer #6 · answered by Zefram 2 · 0⤊ 1⤋