Please Help ASAP: Using the following roots, find the 17th degree polynomial with the lead coefficient one.?

Question

roots: -2, 5, 1 +or- square root of 3i , +or- 2i, +or- square root of 5, +or- 7 square root of 2i, +or- 5 square root of 2, 10, square root 2 + square root 5i, -2+ square root of 5i


just in case u forgot, "i" is complex number or an imaginery number
show work if u can , b/c i tried this problem out but i think i messed up somewhere so i'm trying to see where.

Answer 1

I think there was a mistake in your question.

Did you mean "2 + square root 5i" instead of "square root 2
+ square root 5i"?

Just multiply the folloiwng out:

(x + 2)(x - 5)(x - (1 + sqrt(3i)))(x - (1 - sqrt(3i)))(x - 2i)(x + 2i)(x - sqrt(5))(x + sqrt(5))(x - 7sqrt(2i))(x + 7sqrt(2i))(x - 5sqrt(2))(x + 5sqrt(2))(x - 10)(x - (2 + sqrt(5i)))(x - (-2 + sqrt(5i)))

Answer 2

you can find factors like below
-2 is a root so (x+2) is a factor
5 is a root so (x-5) is a factor
+/-3i are a root so (x+3i)(x-3i) or (x^2+9) is a factor
+/- sqrt 5 are roots (x^2-5) is a factor
+/- 7 sqrt 2 i is a root so (x^2+98) is a factor
so on
multipy all of them and you have the polynomial

Answer 3

3) The graph travels up from scale down left to top good 5) There are 5 turning efficient aspects. to seek out the quantity of turning aspects in a graph all you've were given to do is locate the most excellent exponent for the variable. because the purely right achievable is x^5, the graph has 5 turning efficient aspects. Sorry I are not to any extent further able to do extra. it truly is been a lengthy day and that i'm somewhat drained on the instantaneous. maximum acceptable success!

Answer 4

Boom pop pshhheeee!

Hope that helps. I'm not sure if it was right, but it was ASAP.

Answer 5

first you have to find out if it's an inelastic variant

Answer 6

ask you question properly

Answer 7

I don't THINK so!