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It is circumscribed in a 53072 meter X 65873 meter rectangle.

2006-12-12 19:25:39 · 5 answers · asked by rj serna 1 in Science & Mathematics Mathematics

5 answers

A focus of an ellipse with semi-axes a > b lies at a distance sqrt(a^2 - b^2) from the center.
I think you meant the ellipse was *inscribed* in the rectangle. Then your Q is answered because you know both a and b.

2006-12-12 19:52:08 · answer #1 · answered by Anonymous · 0 0

let a = 65873/2
and b = 53072/2
with the center of the inscribed ellipse at the center of the rectangle.
Then the foci are along the long axis at ± √(a^2 - b^2)

With a circumscribed ellipse the problem gets a little hairier. In fact, it has myriads of possibilities.

2006-12-13 05:28:33 · answer #2 · answered by Helmut 7 · 0 0

atleast read a text book dear. Not all but first 4-5 pages of a chapter, you will find solved questions there.

2006-12-13 03:37:53 · answer #3 · answered by anubhav2k 2 · 0 0

i just know that two foci are possible for an ellipse.
calculate it urself or with the help by the formula provided above .

2006-12-13 08:47:51 · answer #4 · answered by juno 2 · 0 0

http://www.du.edu/~jcalvert/math/ellipse.htm

Here is something all about ellipses.

2006-12-13 03:45:41 · answer #5 · answered by themountainviewguy 4 · 0 0

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