It was half a billion dollars, however the exact details of the contract are confidential. What we do know is that there was a performance clause in there which specified he'd get a bonus in stock options if they exceeded x amount of subscribers in x amount of time, and after Christmas last year they did that. At one time, it was estimated that his deal was valued at around $800 million but Sirius stock prices have dropped significantly since then so the real figure is somewhere between the two.
2006-12-13 15:53:58
·
answer #1
·
answered by Geoff S 6
·
0⤊
0⤋
certain, Howard Stern is properly really worth the 5 hundred million money. On Sirius XM Radio modern convention call Sirius XM Radio presented that 500,000 human beings connect "best of" Sirius vs 2 hundred,000 human beings to "best of XM this kind of shows that the Sirius programming which include Howard has a more advantageous suited draw
2016-11-30 12:36:09
·
answer #2
·
answered by binford 4
·
0⤊
0⤋
I forget the exact number, some hundred million dollars, an insane amount!!! But his TV show is hilarious he has his own station now on demand. Howard TV. I think it's like $20 a month so multiply that by how many peope get it... the guy is banking!!!
2006-12-12 17:14:36
·
answer #3
·
answered by IceyFlame 4
·
0⤊
0⤋
$500 million
2006-12-12 17:11:06
·
answer #4
·
answered by DemoDicky 6
·
0⤊
0⤋
I heard in the 500 million range. He's loaded (even if he never admits it).
2006-12-13 01:31:40
·
answer #5
·
answered by cats 7
·
0⤊
0⤋
I think about $500 million...$100 million each year for a 5 year contract..........more than Sirious is even worth.
2006-12-12 17:04:55
·
answer #6
·
answered by Anonymous
·
0⤊
3⤋
100 million per year, he should donate some of his money to us fokes, lolz
2006-12-12 17:13:20
·
answer #7
·
answered by Raki 3
·
0⤊
0⤋
Howard who?
2006-12-12 17:05:55
·
answer #8
·
answered by wind cries mary 3
·
0⤊
3⤋
$200M worth of stock.
2006-12-12 17:06:11
·
answer #9
·
answered by Anonymous
·
0⤊
1⤋
millions
2006-12-12 17:05:25
·
answer #10
·
answered by ? 7
·
0⤊
3⤋