2006-12-12 15:29:05 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
There are 9 people in the group and 2 are boys. So the odds of the first one being a boy are 2 in 9.
Now when the second person is picked, one of the boys has already been chosen. So there are now 8 candidates, one of whom is a boy. The odds of him being chosen are 1:8. Multiply those two probabilities together: 1/8 * 2/9 = 2/72 = 1/36.
The odds are 1 in 36.
2006-12-12 15:32:37 · answer #1 · answered by Amy F 5 · 0⤊ 0⤋
1 in 36
2006-12-12 15:33:27 · answer #2 · answered by Anonymous · 0⤊ 0⤋
ok so the probability that one the first time is 2/9. then the second time there is 1/8. to find the combination probability, multiply the fractions.
2/9 X 1/8
2/72
Simplify
1/36
2006-12-12 15:33:02 · answer #3 · answered by nightshadyraytiprocshadow 2 · 0⤊ 0⤋
at first, the chances of drawing one boy form the group of 7 girls and 2 boys are 2/9. but should there be one boy left in the group after drawing one boys, the probability of drawing an all-boys leader is:
2/9(initial chances) x 1/8(after drawing one boy)= 2/72 ---> 1/36
2006-12-12 15:38:30 · answer #4 · answered by lpjz290 2 · 0⤊ 0⤋
2/9 x 1/8.
2006-12-12 16:05:19 · answer #5 · answered by Anonymous · 0⤊ 0⤋