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even if you just get me started i would appreciate it. this may look familar but i messed up before

2006-12-12 15:25:11 · 4 answers · asked by dgenerationx97 1 in Science & Mathematics Mathematics

4 answers

The only integral solutions are x = ±2 y = -1, so there are no positive integer solutions.

A computer search finds that

     (11/64)² + (23/16)³ = 3

but, I don't know if there are any others. Perhaps a Google search on "rational points Mordell curve" will help.

Also:

( 130870 / 39³ )² + ( -1873 / 39² )³ = 3

2006-12-13 12:54:59 · answer #1 · answered by p_ne_np 3 · 0 0

x^2 + y^3 = 3
y^3 = -(x^2) + 3
y = cbrt(-(x^2) + 3)

there are multiple answers

for a graph of the multiple answers, go to http://www.calculator.com/calcs/GCalc.html

type in (-(x^2 + 3))^(1/3)

2006-12-12 15:58:19 · answer #2 · answered by Sherman81 6 · 0 0

yupchagee, you gave him a negative root. He wants positive rational roots.

By "rational" do you mean no square roots that are not integers?

2006-12-12 15:37:32 · answer #3 · answered by almintaka 4 · 0 0

x=2
y=-1
2^2+(-1)^3=4-1=3

2006-12-12 15:29:13 · answer #4 · answered by yupchagee 7 · 0 1

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