An object weighing 300 N in air is immersed in water after being tied to a string connected to a balance. The scale now reads 265 N. Immersed in oil, the object appears to weigh 275 N. Find the density of the object and the density of the oil.
2006-12-12 15:00:48 · 2 answers · asked by Jesse 3 in Science & Mathematics ➔ Physics
Density of water=1000kg/m^3
Bouyancy force of water= 35 N because 300-265=35
Water displaced=35N/ (9.81kg/N) =3.567787971 kg displaced.
Volume of object=0.003567788 m^3, because mass displaced over density = volume doing the displacing.
Mass of object=300N/(9.81N/kg)=30.58103976 kg
Density of object=30.58103976kg/0.003567788m^3= 8571.428503kg/m^3
Bouyancy force of Oil=25N
Oil displaced=25N/(9.81N/kg)=2.54841998kg
Density of oil=2.54841998kg/0.003567788m^3= 714.2857086kg/m^3
so for answer you have: density of object=30.58103976 kg/m^3
density of oil= 2.54841998 kg/m^3
plz vote mine best
2006-12-12 15:19:16 · answer #1 · answered by Anonymous 2 · 0⤊ 0⤋
This relies on Archimedes Principal. The density of the object is 300/35 or 8.57 relative to water. The density would be 300/25 or 12 relative to the oil. Thus the oil is 8.57/12 or 0.714 the density of water. I'll leave the units up to you, since in "my day", the answer would be in g/cc.
2006-12-12 15:12:22 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋