What is the quadratic formula?

Answer 1

when you have an equation, such as the following: x^2 +x-1=0, you use the quadratic equation to solve for x. here it is.

[ -b ± (the square root of b^2 - 4ac) ] divided by ( 2a)

now, a is the digit that comes before your x^2 variable
b is the digit that comes before your x variable
c is the digit that has no x multiplier.


so to solve the equation i gave, you would do as follows.

-1 ± ( the square root of 1^2 +4) divided by 2(1)

[-1± the square root of 5] divided by 2

you have two values for x then, one is 1.618033989
the other is -0.618033989

hope i helped vote mine best plz

Answer 2

The Quadratic Formula uses the "a", "b", and "c" from "ax2 + bx + c", where "a", "b", and "c" are just numbers. The Formula is derived from the process of completing the square, and is formally stated as:

For ax2 + bx + c = 0, the value of x is given by:

for more info check the site

Answer 3

If ax^2 + bx + c = 0,

Then the solution for x is

= -b +- sqrt (b^2 - 4ac)
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2a

If b^2 = 4ac, then x has one solution
If b^2 > 4ac, then x has two solutions
If b^2 < 4ac, then x has no real solutions and two solutions that are complex numbers

Answer 4

for an equation of the form ax^2+bx+c=0
x=(-b+/-sqrt(b^2-4ac))/2a

Answer 5

See here:
http://www.purplemath.com/modules/quadform.htm

Answer 6

[-b plus or minus sqrt(b^2 -4(ac)]/2a

ax^2 + bx + c

Answer 7

ax^2 + bx + c

Answer 8

x= -b (plus or minus) Sqrt of (b^2-4ac)
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2a