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2006-12-12 13:46:04 · 5 answers · asked by sparky111 1 in Science & Mathematics Physics

5 answers

I'm assuming you mean the length of one of the rotors is 6 inches.

We'll use this equation to find the amount of power extracted from the wind at 6mph:

-- P = 0.5 x rho x A x V³

• P = power in watts
• rho = air density, standard is about .0764 lbs/ft³
• A = area of rotor swept area (π*.5² = .79 square feet) [Note: I used .5 because I'm finding the area in square feet and 6 inches is one half of one foot]
• V = velocity cubed (6 mph ³ = 216 )

So we have:

P = 0.5 x .0764 x .79 x 216 = 6.518 watts

Therefore, a 6 inch windmill with winds of 6 mph would produce about 6.518 watts of power.

2006-12-12 14:24:33 · answer #1 · answered by FallenOrigin 2 · 0 0

It depends on the components your windmill is connected to- Use equations like EMF (Electromotive Force) and transformer calculations to determine how fast your iron core or other core is going through the coils in the transformer in question to produce alternate current (and voltage based on the size of your magnetic field). You will also need to determine the permeability of the metals you are using to calculate inductance, capacitance, resistance, and so on. Your question involves both electromagnetism and electronic formulas to derive your final answer, which can get very complex. You need more information on the materials you are using and the size or amounts of material you are using (plus, the way you wind your coils also affects the output too).

2006-12-12 22:00:37 · answer #2 · answered by Anonymous · 0 0

The correct question is how much power does a windmill produce. Power is energy per unit time.

You have not included enough data to calculate power, which is equal to torque times rotaional speed.

2006-12-12 22:00:01 · answer #3 · answered by David H 4 · 0 0

Depends on the generator/alternator.

2006-12-12 21:59:45 · answer #4 · answered by Scarp 3 · 0 0

12 volts don't know would depend on lots of things.

2006-12-12 21:48:15 · answer #5 · answered by Anonymous · 0 0

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