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solve the equation for the given number
L=2b^2/a ;a
show process please

2006-12-12 13:28:38 · 2 answers · asked by fiori3092 3 in Science & Mathematics Mathematics

i need to see if i did it right

2006-12-12 14:31:41 · update #1

2 answers

From your question, this is what I am interpreting:

Solve the equation for 'a': L = (2b^2)/a

If this is the case, this is how you do it.

First, multiply both sides by a:
a*L = 2b^2

Then divide both sides by L to isolate a:
a = (2b^2)//L

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Hope this helps

2006-12-12 15:19:23 · answer #1 · answered by JSAM 5 · 0 0

you need to explain a lot of this, is this L=2b^(2/a) or L=(2b^2)/2a or even possibly L=2(b^2)/a? What does the ";a" mean? Does that mean in terms of a? Do you know how to differentiate/take the derivative?

2006-12-12 21:36:35 · answer #2 · answered by americanmimeboy 4 · 0 1

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