soluble ammonium chloride forms, and copper (II) phosphate precipitates out of the solution?
Please help.
2006-12-12 13:23:35 · 3 answers · asked by Random G 3 in Science & Mathematics ➔ Chemistry
Oh, and also, what is the ionic equation for this same reaction?
2006-12-12 13:24:57 · update #1
3CuCl2(aq)+2(NH4)3PO4(aq) ---> 6NH4Cl(aq) + Cu3(PO4)2(s)
net ionic rxn:
3Cu(2+)(aq) + 2PO4(3-)(aq) --> Cu3(PO4)2(s)
2006-12-12 13:34:32 · answer #1 · answered by Math-Chem-Physics Teacher 3 · 0⤊ 0⤋
The balanced equation is: CuSO4*5H2O + 2 NH4Cl = (NH4)2SO4 + CuCl2 + 5 H2O One mole of Copper Sulfate Pentahydrate and two moles of Ammonium Chloride form one mole of Ammonium Sulfate and Copper (II) Chloride or Cupric Chloride and five moles of water.
2016-03-29 05:10:00 · answer #2 · answered by Anonymous · 0⤊ 0⤋
3CuCl2(aq)+2(NH4)3PO4(aq) --->
6NH4Cl(aq) + Cu3(PO4)2(s)
charges in parentheses are superscripts
all ions aqueous unless specified otherwise
overall ionic eq
3Cu(2+) + 6Cl(-) +6NH4(+) + 2PO4(3-) --->
6NH4(+) + 6Cl(-)+ Cu3(PO4)2(s)
cancel particles present on both sides to get
net ionic eq
3Cu(2+)(aq) + 2PO4(3-)(aq) --->
Cu3(PO4)2(s)
6Cl(-) +6NH4(+) are spectator ions
2006-12-12 13:31:26 · answer #3 · answered by rm 3 · 0⤊ 0⤋