Geometry Help?

Question

The width of a rectangle is one-third of the length. If the rectangle's perimeter is 40 cm, what are the dimensions of the rectangle?

Answer 1

x = width
3x = length

Perimeter = 2[x + 3x] = 2(4x) = 8x = 40
x = 5

Dimensions of the rectangle are:
width = x = 5
length = 3x = 15
So the rectangle is 5 by 15.

Answer 2

Width is 1/3 of length. or length is 3 times the width.

So, width + length is 4 times the width.

Therefore, the perimeter, which is 2 times the (width + length), is 8 times the width.

If 8 times the width is 40 cm, the width is 40/8 = 5 cm. An length is 3 times this, = 15 cm.

Answer 3

see if i did this right....2L+2W=p or 40cm
so..w=1/3L and then 2L+2(1/3)L= 40cm ..p
2L+2/3L=40
8/3(L)= 40cm
(3/8)times L = 120/8= 15 for length and 1/3 of that = 5 so 5 by 15 are the the dimensions. check work, 5+5+15+15= 40 cm perimeter! hey I worked on this a long time and can help you with trig or analytical stuff too! brain damaged at this time!!! good luck to you!

Answer 4

Make the width of the rectangle "x".
The length would be "3x"
Then you can figure that the whole perimeter is "8x"
8x=40
x=5

The rectangle is 5 by 15

Answer 5

hm....well i'd start off my labeling variables....so.... the length would be "x" and the width would be "(1/3)x".

Then just plug into the perimeter equation.....

2x + 2(1/3)x = 40....

add the x's.... 8/3x = 40.....divide and x = 15 so....length equals 15 and the width equals one third or 5...

Answer 6

(w+1/3w)2=40
w=15

1/3 of 15 is 5

so 5 by 15

Answer 7

Set the problem up as so:

2x + 2y= 40cm

y=1/3x

substitute values and do a little algebra and you will have your answer. I take it that this is homework? So I gave you some help. You will have to solve it yourself!

Answer 8

l=27
w=13.333333...