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__KNO3(s) --> __ KNO2(s) + ___ O2(g)
__Ag2O(s) ---> ___Ag(s) + ___ O2(g)
__C4H10(g) + __O2(g) ---> ___CO2(g) + ___ H2O(g)
__Br2(aq) + ___ )KI(aq) --> ___I2(aq) + ____KBr(aq)
___AsCI3(aq) + ___H2S(aq) ---> ___As2S3 (s) + ___H2O (g)

2006-12-12 12:54:19 · 3 answers · asked by Danyizzle 4 in Science & Mathematics Chemistry

3 answers

1. 2, 2, 1

2. 2, 4, 1

3. 2, 13, 8, 10

4. 1, 2, 1, 2

5. won't balance, there isn't any Cl on the right


For 1 and 2, start by putting a two on the compound by itself(the left side) and then fill in the other side according to that.

For 3, look at the C4H10 on the left and fill in the right to match. Then look at the two O's on the right and fill in the lone O2 on the left (if the O2 comes out to be a half number, double all your numbers to make wholes)

For 4, notice the elements with the 2's. Follow those elements to thier respective opposite sides, and double KI and KBr.

2006-12-12 13:10:36 · answer #1 · answered by benmesch 2 · 0 0

1. would be 2 -> 2 + 1
2. 2 -> 4 + 1

2006-12-12 20:58:44 · answer #2 · answered by drewms64 2 · 0 0

2KNO3(s) --> 2 KNO2(s) + O2(g)
2Ag2O(s) ---> 4Ag(s) + O2(g)
Br2(aq) + 2KI(aq) --> I2(aq) + 2KBr(aq)
2AsCI3(aq) + 3H2S(aq) + 3O---> As2S3 (s) + 3H2O (g) + 3 Cl

2006-12-12 21:11:15 · answer #3 · answered by jamaica 5 · 0 0

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