2006-12-12 12:21:50 · 23 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
20c + 5 = 5c + 65
group like terms: (20-5)c=65-5
Simplify: 15c = 60
divide by 15 to isolate c: 15c / 15 = 60 / 15
c = 4
2006-12-12 12:24:54 · answer #1 · answered by Joel M 2 · 0⤊ 0⤋
C = 4
2006-12-12 12:29:47 · answer #2 · answered by lyssa1913 2 · 0⤊ 0⤋
20c+5=5c+65
subtract 5c from both sides of the = sign
15c+5=65
subtract 5 form both sides of the = sign
15c=60
divide both sides by 15
c=4
because
20c+5=5c+65
20multiplied by 4plus 5 equals5 multiplied by 4 plus 65
2006-12-12 12:47:32 · answer #3 · answered by utony16 2 · 0⤊ 0⤋
20c = 5c + 65 - 5 (subtract 5 from both sides)
20c = 5c + 60 (sum 65 & -5)
15c = 60 (subtract 5c from both sides)
c = 60/15 (divide each side by 15)
c = 4 (divide 60 by 15)
2006-12-12 12:26:04 · answer #4 · answered by Gene 3 · 0⤊ 0⤋
c=4
2006-12-12 12:34:37 · answer #5 · answered by Jake 2 · 0⤊ 0⤋
20c+5=5c+65
First of all you need isolate the variable "c":
So, passes all variables to the left side of the equation:
20c + 5 - 5c = 65
And all the numeric terms tothe right side.
20c -5c = 65 -5
So sum the terms of the left member
15c =65 -5
And the terms of the right member of the equation
15c =60
Now, isolate c
c= 60/15
c= 4
2006-12-12 12:29:53 · answer #6 · answered by Carlos M 7 · 0⤊ 0⤋
c=4
2006-12-12 12:24:05 · answer #7 · answered by Anna 2 · 0⤊ 0⤋
20C + 5 = 5C + 65
20C - 5C = 65 -5
15C = 60
C = 60/15
C = 4
2006-12-12 12:28:59 · answer #8 · answered by Tim E 3 · 1⤊ 0⤋
20c+5=5c+65
20c-5c=65-5
15c=60
15c/15 = 60/15 divide both sides by 15
c=4
i tried to go step by step. hope you understood.
2006-12-12 12:25:58 · answer #9 · answered by Anonymous · 0⤊ 0⤋
subtract 5c from both sides= 15c+5=65, subtract 5= 15c=60 then divide by 15, answer is c=4
2006-12-12 12:28:15 · answer #10 · answered by TRG 2 · 1⤊ 0⤋