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yah this is for homework but im desperate........
andrew placed a sample of gold in 200ml of receiving water inside a 50 gram beaker. (the beakers mass should be included in the calculation of the specific heat). the starting temperature of the receiving water was 20.0 degrees celcius. the ending temperature of the water was 30.0 degrees celcius. the hot temperature of the gold was 90.0 degrees celcius. based upon current marketing conditions, wat is the value (in american dollars) of the gold which andrew is using in his experiment.........use significant digits.........if u cant give me the answer pls just give me a tip im desperate

2006-12-12 12:21:14 · 4 answers · asked by Anonymous in Education & Reference Homework Help

4 answers

you should not sheep on Ricks lab.
use the specific heat for gold and then multiply...oh well.
DON"T SHEEP!!!
its bad.

2006-12-12 17:43:06 · answer #1 · answered by Anonymous · 0 0

Get a pen and paper and write out the problem and then draw a pic of the object and then the weight or what ever it says. After that think of it, Is it multiply, Divided, Add, Subtract, Convers, ect. Thats what i would do. GOOD LUCK!!!!!

2006-12-12 12:32:58 · answer #2 · answered by wuz up 1 · 0 0

heat lost or gained = m c t ( m= mass, c= sp heat capacity and t= diff between initial and final temp)
here heat lost by gold = m( to be calculated) multiplied by sp heat cap of gold (look it up in table) multiplied by60
heat gained by water=200multiplied by 4.2 multiplied by10
heat gained by beaker=50 mulplied bysp heat cap of beaker(look it up )multiplied by 10. now equate ht lost =ht gained.calculate mass of gold frm this.look up price of gold in newspaper and multiply mass and current price

2006-12-12 14:08:53 · answer #3 · answered by calmserene 4 · 0 0

I might if I could but math was never my thing. Sorry.

2006-12-12 12:28:40 · answer #4 · answered by Anonymous · 0 0

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