Find the value of k + w given the following.?

Question

a rhombus has a perimeter of 96, and the length of one of its diagonals is 32. the area of the circle inscribed in the rhombus can be expressed as k(pi)/w where k and w are relatively prime positive intergers.

Answer 1

A rhombus has four equal sides, so each side of the rhombus is 96/4 or 24.
The other diagonal would split the 32-diagonal in half.
The resulting right triangle has a hypotenuse of 24 and a side of 16. The other side would be 8sqrt5, so that diagonal is 16sqrt5.
The 32-diagonal is the shortest diagonal, so the circle would have radius 16.