Could somebody help me with these 3 chemical equations?

Question

i reckon these are the Redox equations...but still be done the same way Probally:
These are done the Redox Way....
1) Bi2 S3 + HNO3 >>>> Bi (NO3)3 + NO + S + H2O
2) K2 Cr2 O7 + HCl >>>> KCl + CrCl3 + Cl2 + H20
3) HgS + HCl + HNO3 >>>> Hg Cl2 + NO + S + H2O

Answer 1

1) Bi2 S3 + 8HNO3 >>>> 2Bi (NO3)3 + 2NO + 3S + 4H2O
Note that S-2 >>>> S + 2 e- being oxidized
N+5 +3e- >>>>>N+2 is being reduced
2) K2 Cr2 O7 +14 HCl >>>>2 KCl + 2CrCl3 + 3Cl2 + 7H20
Cr+6 + 3 e- >>>>> Cr+3 (oxidation)
2Cl-1 >>>>>>> Cl2 + 2 e- ( reduction)
3) 3HgS + 6HCl + 2HNO3 >>>> 3Hg Cl2 +2NO + 3S + 4H2O
S-2 >>>>> S + 2 e- (oxidation)
N+5 + 3 e- >>>>>>>N+2 (reduction)
Make sure that oxidation is balanced by reduction and the rest is pretty simple.