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2b sqaured(b+5) - 5b(b sqaured +3b+4)

2006-12-12 11:49:23 · 3 answers · asked by kageepan_k 1 in Education & Reference Homework Help

3 answers

2b ^2 (b+5) - 5b(b^2 +3b+4)

then you have to distribute the quantities in
2b^3 + 10b^2 - 5b^3 -15b^2 - 20b

and your answer isss after combining like terms
-3b^3 -5b^2 - 20b

btw - ^ means to the power of

2006-12-12 11:53:37 · answer #1 · answered by Anonymous · 0 0

distribute the #'s outside the parenthesis to the numbers inside:
2b sq*b i= 2b cubed, 2b sq*5 is 10b sq, 5b sq*b sq is 5b^7, etc. you should get: 2b^3+10b^2-5b^7+15b^2+20b then combine like terms(10b^2+15b^2) and the final answer should be:
-5b^7+2b^3+25b^2+20b

2006-12-12 19:57:50 · answer #2 · answered by Shway-Z_86 2 · 0 0

=2b cubed +10 b squared -5 b cubed -15 b squared -20b

= -3b cubed - 5 b squared -20b

2006-12-12 19:58:44 · answer #3 · answered by calmserene 4 · 0 0

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