7(3x+4)=8(2x+5)+13
21x+28=16x+40+13
21x-16x=40+13-28
5x=25
x=5
2(x-6)-3(x+5)=3(x-2)-7
2x-12-3x-15=3x-6-7
-1x-27=3x-13
-4x=40
x=-10
3x-5(3x-7)=2(x+9)=45
3x-15x-35=2x+18=45
-14x-53=45
-14x=98
x=-7
2006-12-12 11:55:15
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answer #1
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answered by M 4
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This one's a bit complicated, but still simple if you take it step by step. The first step would be to get rid of the brackets because brackets suck. So if you expanded the first brackets, you would get: -6(x+3) = (-6*x) + (-6*3) = -6x - 18. Now expand the second brackets: 3(-2x-5) = (3*-2x) + (3*-5) = -6x - 15 So when you substitute these into the equation (if you put -6x-18 instead of -6(x+3), it wouldnt change the equation because you showed that both of them are equal) -6x - 18 - 10 = -6x - 15 - 13 -6x - 28 = -6x - 28 0 = 0, so you just showed that it doesn't matter what x is, the equation will still be valid. Because the x ends up cancelling itself out. If you were finding the intersection point, then it would mean that the 2 lines are lieing on top of each other because they are equal at any and all x points. Hope that helped
2016-05-23 16:14:41
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answer #2
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answered by Anonymous
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21x+28=16x+53
5x=25
x=5
-x-27=3x-13
-4x=14
x=-3.5
-12x+35=2x+18=45 im going to assume the =45 should be +45
-28=14x
-2=x
2006-12-12 11:55:02
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answer #3
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answered by jekelly90 2
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7(3x+4)=8(2x+5)+13
21x+28=16x+40+13
5x=25
x=5
2(x-6)-3(x+5)=3(x-2)-7
2x-12-3x-15=3x-6-7
4x=-14
x= -3.5
3x-5(3x-7)=2(x+9)=45
3x-15x+35=2x+18+45
14x= -28
x= -2
2006-12-12 11:55:09
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answer #4
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answered by A 150 Days Of Flood 4
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7(3x+4)=8(2x+5)+13
=21x+28=16x+40+13
=21x-16x=53-28
=5x=25
=x=25/5
x=5
2006-12-12 12:04:40
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answer #5
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answered by earl_sykes_101@hotmail.com 2
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1. x=5
2. x=4
3. x=13 (?)did you mess up while typing this one?
2006-12-12 11:59:26
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answer #6
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answered by bwiz19 1
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21x+4x=16x+40x+13
56x-21x= -13
35x= -13
x= - 35/13
x= - 2.70
2006-12-12 11:50:35
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answer #7
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answered by afghaniguy007 2
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hang on iam writing the answers
2006-12-12 12:02:55
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answer #8
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answered by Anonymous
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