How do u write a equation.... of the line that contains the point (8,-3) and is perpendicular to 4x-3y=10?

Answer 1

Find the slope of the given line by solving for y.
4x - 3y = 10
-3y = -4x + 10
y = (4/3)x - 10/3
The slope is 4/3
The slope of a line perpendicular to this one is the negative reciprocal, so the slope is m = -3/4
y - (-3) = (-3/4)(x-8) is the equation you are looking for.
You may wish to write it as
y + 3 = (-3/4)x + 6
y = (-3/4)x + 3

Answer 2

Use the point - slope formula!!!

First - solve for y:

4x-3y=10
4x-10=3y
(4x-10)/3=3y/3
4/3x-10/3=y

Put into linear equation form:

y=4/3x-10/3

The perpendicular line has a slope that is the negative inverse of the slope in the original: -3/4

Use the point-slope formula now that you know the slope:

y-y1=m(x-x1)
y-(-3)=-3/4(x-8)
y+3=-3/4x-6
y=-3/4x-9

Answer 3

Find the slope of the given line. In your case, it is 4/3. Take the negative reciprocal (-3/4). That is the slop of the perpendicular line. Then use the points given to find the "b" in y=mx+b equation for a line.

Answer 4

A perpendicular line must have the inverse gradient of the line it intersects. I.e m1*m2 =-a million. we may be able to rearrange the given equation to the style y=mx+c to grant us the gradient. 4x-10=3y 4/3x-10=y. hence, the gradient of line a million is 4/3. because both gradients ought to multiply to equivalent -a million, 4/3*m=-a million m=-a million/(4/3) m=-3/4 Now we use the point-gradient equation to ensure an equation for the hot line. y-y=m(x-x1) y--3=-3/4(x-8) y+3=-3/4(x-8) 4y+12=-3(x-8) 4y+12=-3x+24 4y=-3x+12. in case you opt for, you should totally simplify right down to: y=-3x/4+3. also, to be stylish, you should exhibit it as: 3x+4y-12

Answer 5

Perpendicular means 90 degree angle to the line.......

Line can be rewritten as (4x-10)/3 = y

so......negative reciprocal of slope is perpendicular -3/4

if you plug into point slope form.............. y+3=-3/4(x-8)

Answer 6

slope of 4x-3y=10
=4/3
slope of perpendicular line(m)=-3/4
equation
y-y1=m(x-x1)
y+3=-3/4(x-8)
4y+12=-3x+24
4y+3x=12

Answer 7

slope of the given line,4x-3y=10is
-xcoeff/ycoeff.
The slope is 4/3
The slope of a line perpendicular to this one is the negative reciprocal, so the slope of perpendicular line is m = -3/4
so,putting it in y=mx+b form,
y = (-3/4)x + 3...

hope u are satisfied..