=10x-5-(-9x sqaured-12x)
=10x-5+9x sqaured +12x
=9x sqaured +22x-5
Explain the error in each expansion then show the steps for a corrected solution.
2006-12-12 11:07:17 · 3 answers · asked by kageepan_k 1 in Education & Reference ➔ Homework Help
The expansion error occurred when the 5 was distributed at the same time the 3x term was distributed. Also, the negative sign in front of the 3x got distributed twice. Here is a correct solution process if there is supposed to be another parenthesis after the 3x+4 term.
5(2x - 10 - (9x^2 + 12x))
5(2x - 10 - 9x^2 -12x)
5(-9x^2 - 10x - 10)
-45x^2 - 50x - 50.
If a parenthesis was left out after the 2x - 10 term, the solution would be:
5(2x - 10) - 3x(3x + 4)
10x - 50 - 9x^2 -12x
-9x^2 - 2x - 50.
2006-12-12 11:23:15 · answer #1 · answered by iuneedscoachknight 4 · 0⤊ 0⤋
I can't answer it yet, did you mean 5{2x-10-3x(3x+4)}? If that is what you meant I can solve it
1) 5(2x-10-9x^2-12x)
2) 5(-10x-10-9x^2)
3) -50x-50-45x^2
4) do You need to solve for x?
x=1/2
2006-12-12 19:10:28 · answer #2 · answered by Anonymous · 0⤊ 0⤋
ITS ALL WRONG
the answer is:
-45x²+ 10x - 110
5(2x-10-3x(3x+4))
5(2x-10-9x²-12)
10x-50-45x²-60
-45x²+10x-110
2006-12-12 19:16:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋