acceleration is .46m/s^2, how long would it take them to go 10 m.
I know the answer is 6.5 seconds, I just don't know how to find 6.5 seconds.
2006-12-12 10:01:45 · 3 answers · asked by w_xsoadx_w 2 in Science & Mathematics ➔ Physics
Our basic equations of motion tell us that an objects position, I'll say x, is
x = 1/2 a t^2 + vt + x_0,
where a is acceleration, t is time, v is the initial velocity, and x is the initial position. Assuming that the initial velocity and initial position are zero, you are left with
10 m = 1/2 a t^2.
Solve for time from there.
2006-12-12 10:08:39 · answer #1 · answered by woocowgomu 3 · 1⤊ 0⤋
you just have to know the formulas and how to use them
remember:
d=1/2 a t ^2
you have the distance, you have the acceleration, you can solve for time
10=.5 (.46)t^2
10/(.5)(.46)=t^2
sqrt(10/(.5*.46))=t
I get 6.6 seconds.
good luck, keep at it
2006-12-12 18:10:03 · answer #2 · answered by enginerd 6 · 0⤊ 0⤋
a = .46m/s^s
x = 10m
vo = 0 m/s
Use this equation:
delta x = vo * t + .5a * t^2
:)
2006-12-12 18:18:45 · answer #3 · answered by Grand Master Flex 3 · 0⤊ 0⤋