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Number of tests taken/ Number of students

0/12
1/8
2/2
3/3
4 or more/5
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If a student is selected at random, find the probability
a)the student has taken exactly two tests
b)the student has taken at least two tests
c)the student has taken at most three tests
d)the student has taken 3 or fewer tests
e)the student has taken one or two tests.

2006-12-12 09:59:18 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

so we know our sample isze is 30 making n=30.

Lets start with a.

2 students took 2 tests so P = 2/n = 2/30 = 1/15

b) At least 2 tests means you could have take 2 or 3 or 4 or more. Thus,

P = (2+3+5)/n = (10)/30 = 1/3

c) At most three tests means 0, 1, 2, or 3., thus:

P= (12+8+2+3)/n = 25/30 = 5/6

d) If you have taken 3 or fewer tests, that is the same as at most three tests so the answers is the same as c.

3) One or two tests is when using th elogic above.

P = (8+2)/30 = 1/3

2006-12-12 10:04:30 · answer #1 · answered by Zayd 2 · 0 0

a) 2 people have taken 2 tests = 2/30
b) 12 have 0 tests, 8 have 1 = 20 have taken less than 2 meaning 30-20 = 10 have taken at least 2 p =10/30

c) 5 have taken 4 or more 30-5 = 25 = number who have taken at most 3 p =25/30

d) same as c.

e) 8 have 1 and 2 have 2 = 10/30

2006-12-12 10:05:22 · answer #2 · answered by Modus Operandi 6 · 0 0

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2016-12-18 12:19:17 · answer #3 · answered by Anonymous · 0 0

a) 6.67% 2/30 students
b)33.33% 10/30 students
c)83.33% 25/30 students
d)83.33% 25/30 students
e)33.33% 10/30 students

2006-12-12 10:07:37 · answer #4 · answered by Scott S 2 · 0 0

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