A can of paint will cover 70 square feet. How many cans are needed to paint a wall 5 feet high and 98 feet long?
2006-12-12 09:52:05 · 6 answers · asked by Jen 1 in Science & Mathematics ➔ Mathematics
no of cans=area of the wall/area onecan can paint
=98*5/70
=7 cans
2006-12-12 09:54:37 · answer #1 · answered by raj 7 · 0⤊ 0⤋
7 cans.
Make it in a fraction-> 1can of paint over 70 square feet = ? over 490 square feet (5 X 98)
Then to find out the question mark you would cross multiply (1X490)= 490 Then divide your answer by 70 (490/70=7)
So it would take seven cans to cover 490 square feet or a 5 x 98 foot wall.
2006-12-12 18:00:33 · answer #2 · answered by Jordan 2 · 0⤊ 0⤋
How many square feet will 2 cans cover? You had better answer 140 square feet!
Now how many square feet is a wall 5 feet by 98 feet? Divide by 70 to get the number of cans. You may need to round up if there is a partial can involved.
2006-12-12 17:56:13 · answer #3 · answered by rscanner 6 · 0⤊ 0⤋
Hello
First we find the sq. feet of the wall
98 x 5 = 490
490 / 70 = 7
7 cans of paint are needed
2006-12-12 18:00:39 · answer #4 · answered by Anonymous · 0⤊ 0⤋
5 x 98 (to find area)
=490
Then to find how many cans....
490 / 70
=7....
So you need 7 cans of paint.
2006-12-12 17:55:32 · answer #5 · answered by ViCKi!™|` 5 · 0⤊ 0⤋
you need 7 cans of paint, and an extra can if you roll it on too thick.
2006-12-12 17:55:22 · answer #6 · answered by Anonymous · 0⤊ 0⤋