2006-12-12 09:40:34 · 8 answers · asked by lindahough 1 in Science & Mathematics ➔ Chemistry
start with the carbons
there are 6 on the left side so but a 6 in front of CO2
then hydrogens
there are 12 on the left side, so put a 6 in front of H2O (making 12 hydrogens on right also)
carbons good, hydrogens good, just need the oxygens
right side has 18 oxygens so put a 6 in front of O2 on left side giving 12 oxygens there plus the 6 in the hydrocarbon
C6H12O6 + 6O2 --> 6CO2 + 6H2O
voila
2006-12-12 09:46:37 · answer #1 · answered by enginerd 6 · 1⤊ 0⤋
C6H12O6 + O2 --> CO2 +H2O
In the balancede form we have:
C6H12O6 + 6O2 ---> 6CO2 + 6H2O
C -6 , H -12 and O - 18
in both sides.
2006-12-12 09:45:55 · answer #2 · answered by Carlos M 7 · 1⤊ 0⤋
C6H12O6 + 6 O2 --> 6 CO2 + 6 H2O
This is the reaction for respiration process in which glucose (C6H12O6) reacts with oxygen (O2) to produce CO2 and water (and energy, not shown).
2006-12-12 09:45:07 · answer #3 · answered by myyahoo! 2 · 0⤊ 0⤋
C6H12O6 + 6-O2 --> 6-CO2 +6-H2O
2006-12-12 09:46:30 · answer #4 · answered by MЯ BAIT™ 6 · 0⤊ 1⤋
1; 6; 6; 6
2016-05-23 15:49:56 · answer #5 · answered by Anonymous · 0⤊ 1⤋
C6H12O6 + 6O2--> 6CO2+6H2O
2006-12-12 09:54:53 · answer #6 · answered by The Tank 3 · 0⤊ 1⤋
C6H12O6 + 6O2 --> 6CO2 +6H2O
2006-12-12 09:44:19 · answer #7 · answered by Brenmore 5 · 0⤊ 1⤋
C6H12O6 + 6O2 ----> 6CO2 + 6H2O
2006-12-12 09:46:42 · answer #8 · answered by David S 2 · 0⤊ 1⤋