the hypotenuse of a right triangle is 15 centimeters long. one leg is 9 centimeters long. how long is the other leg?
2006-12-12 08:34:09 · 7 answers · asked by shawn 1 in Science & Mathematics ➔ Mathematics
a^2+b^2=c^2
pluggingin
15^2=x^2+9^2
x^2=225-81=144
x=rt144
=12
the other leg is 12cm.
2006-12-12 08:38:25 · answer #1 · answered by raj 7 · 1⤊ 0⤋
12 centimeters
2006-12-12 08:43:59 · answer #2 · answered by amslseaman 1 · 0⤊ 0⤋
the other leg would be 12 because c^2=a^2+b^2
15^2=9^2+b^2
225=81+b^2
225-81=81-81+b^2
144=b^2
the square root of 144=b^2
12=b
2006-12-12 08:45:17 · answer #3 · answered by ♥KiYa♥ 3 · 0⤊ 0⤋
a^2 + b^2 = c^2, pythagoras theorem
9^2 + b^2 = 15^2
81 + b^2 = 225
b^2 = 144
b = 12
2006-12-12 08:36:44 · answer #4 · answered by slider 2 · 1⤊ 0⤋
12 it a 3,4,5 triangle multiplied by 3 hence 9,12,15
2006-12-12 08:43:34 · answer #5 · answered by richiec 2 · 0⤊ 0⤋
This is a 3,4,5 triangle. or a 9,12,15 in this case. Remember the 3,4,5
2006-12-12 08:41:29 · answer #6 · answered by snfcricket 3 · 0⤊ 0⤋
using the phytagoras formula
hypo²=side²+side² ...............we can put that to
side²=hypo²-side² ..............subtracting -side² from it
side=SQR(hypo²-side²) .............pulling squareroot
side=SQR(15²-9²) ............put in values
side=SQR(225-81) ..........and then
side=SQR(144) ............and then
side=12cm ......... there we are
2006-12-12 08:45:40 · answer #7 · answered by blondnirvana 5 · 0⤊ 0⤋