Algebra Help...?

Question

I have some math problems i do not get so i just need help firuing out in steps.. how to combine exponets...

1. 10a to 4th b to the 7th all over -5a to the 9 and b to the 2 i know it is confusing how i put it but it wont let me do the exponets.. well some GOOD feedback would be nice ty!! Ps: i am only 12 lmao

Answer 1

First off, when you want to type out exponents use the "^" sign. Don't ask why, it's part of the way they used to program mainframe computers back in the 40s and 50s. Also, use * for multiplication, and you can never go wrong with using parantheses. So:

[(10*a^4)*(b^7)]/[(-5a^9)*b^2)]

Still confusing, so if you really want to you could write it out like:

(10*a^4)*(b^7)
------------------
(-5a^9)*b^2)

Ok. To solve this problem, you have to remember two things: First, that an exponent in the denominator is the same as a negative exponent in the numerator. So this is the same as:

(10*a^4)*(b^7) * (a^-9)*(b^-2)
-------------------------------------
-5

Second, remember that once you have everything in the numerator, you can add and subtact exponents when the have the same base. So:

a^4* a^-9 = a^-5
b^7*b^-2 = b^5

Using the same logic, a negative exponent in the numerator is the same as a positive exponent in the denominator. So now you have:

(10*a^-5)*(b^5)
------------------- =
-5


10*b^5
---------
-5*a^5

Remember to simplify the 10/-5 and you get:

-2*b^5
---------
a^5

you could also write this like:

-2*(b/a)^5

Hope this helps. PS, each of the above answers is wrong. The -2 is in the numerator not in the denominator like "grad student" has it; and God knows where the 8 in the other answer came from.

Answer 2

10a^4 b^7 / -5a^9 b^2

the answers is going to be -8b^5 / a^5

to get that answer you have to divide the integers and move the little exponents to the big exponets and subtract them.

Answer 3

I'll help you, i'm good at algebra.. but you have to put the problem like it is stated so that i can help you:]

P.S. [dont put it in words], write out the question again and i'll anwer it

Answer 4

10a (4) b (7)
----------------
-5a (9) b (2)

=

-2b to the fifth
----------------
a to the fifth




How:
x^m = x^m - x^n
-----
x^n

AND: x^-m =
1
-----
x^m


There ya go!