one number is 2 times larger than another. the sum of their reciprocals is 3/16 determine the two numbers?

Answer 1

let the nos be x and 2x
1/x+1/2x=3/16
(2+1)/2x=3/16
cross multiplying
48=6x
dviding by 6
=8
the nos are 8 and 16
check
1/8+1/16=3/16 checks

Answer 2

enable x and y be the numbers you're seeking for. Now, you recognize that one style is 4 situations the different style, so which you will say: x = 4y additionally, you recognize their reciprocals upload as much as equivalent a million/8, so a million/x + a million/y = a million/8 Now, you could replace x with 4y in the above equation: a million/4y + a million/y = a million/8 Now, hit upon a basic denominator for the left area of the equation. the superb basic denominator is 4y: a million/4y + 4/4y = a million/8 5/4y = a million/8 Now, circulate multiply: 4y(a million) = 5(8) 4y = 40 y = 10 on the grounds which you recognize that x = 4y, and you presently understand that y = 10, resolve the equation to discover x: x = 4y x = 4(10) x = 40 So, x = 40 and y = 10

Answer 3

Let x = first number and y = second number.

x = 2y
1/x + 1/y = 3/16.

Plug in 2y for x in the second equation,
1/2y + 1/y = 3/16

Get a common denominator and solve for y, and you get 8. since x = 2y and y = 8, then x must be 16.

Answer 4

8 and 16
2 x 8 = 18

1/8 + 1/16 = 3/16

Answer 5

(1/x) + (2/x) = 3/16

1/x + 2/X = 3/16

1/16 + 2/16 = 3/16

1/16 and 1/8 are the numbers

Answer 6

let the 1st no = x , the second no = y
x=y+2 equation(1)
1/x+1/y=3/16
x+y=16/3 equation(2)
by adding the 2 equations
2x=22/3
x=11/3
y=5/3

Answer 7

Let # = X

1/X + 1/2X = 3/16
2X/2X + 1/2x = 3/16

3/2X = 3/16

6X = 48

X = 8
2X = 16

1/8 + 1/16 = 3/16