In big blind and small blind at nine person table, doubt that matters tho.
2006-12-12 06:48:09 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The same as getting dealt any two specific cards. The chances of getting those two specific cards are 1/ (52 * 51) ... 52 choices for first card, 51 for second. This equates to 0.000377, or 0.0377%, or 1 in 2,652.
2006-12-12 07:01:15 · answer #1 · answered by chris_garman 2 · 1⤊ 0⤋
The same exact hand (same suit) is 1 in 1,326. The same two numbered cards is 1 in 85.
2006-12-12 15:00:22 · answer #2 · answered by syphongalaxy 2 · 0⤊ 1⤋
Somebody forgot to shuffle.
2006-12-12 14:55:59 · answer #3 · answered by Ricky J. 6 · 0⤊ 0⤋
1/(52 C 2) = 7.5x10^-4
2006-12-12 14:51:07 · answer #4 · answered by jacinablackbox 4 · 0⤊ 2⤋
Slim to none....
2006-12-12 14:52:25 · answer #5 · answered by Anonymous · 0⤊ 0⤋