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Ok I have a series-parallel circuit. I know that:
V(T) = 60 V
I(T) = 2 A
V(R2) = 30 V
R(3) = 30 Ohms

I have to find

V(R3)
R(2)
R(1)

Now I find V(R3) I think by doing the following:

V(R3) = V(T) - V(R2)
V(R3) = 60 V - 30 V
V(R3) = 30 V

If that is correct please... I beg you... Help me Find:

R(2)
R(1)

In that order. Please. I would post a diagram, but I can't do that on here but I can tell you that there are 3 resistors. Imagine a square box. Now make a line down the middle. Now put in a resistor (#3) on the right side of the box. now put another (#2) on the bottom right side. now put one(#1) on the line that divides the box in half. now on the left side is the voltage. I hope this help... Ok I'm going to shut up now.

Thank you deeply for any help you can provide me.

2006-12-12 06:23:10 · 3 answers · asked by ? 2 in Science & Mathematics Mathematics

3 answers

Ok, here's another crack after reading the whole thing. You were indeed correct about the first one. R2 is going to drop 30V. Which means that R2 is going to be the same value as R3 (since R2 is dropping half of the voltage and R3 is the only other resistor in that branch, so it has to drop the other 30V). R1 is going to drop 60V. Figure out how many Amps are flowing through the first side by using Ohm's law. I = V/R. I = 60V/(30Ohms+30Ohms). I = 1A. Which means the other 1 amp is flowing through the other branch. We'll again use Ohms law. R = V/I. R = 60V/1A. R1 = 60 Ohms.

2006-12-12 06:29:42 · answer #1 · answered by Chris J 6 · 2 0

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2016-11-25 23:05:30 · answer #2 · answered by jowers 4 · 0 0

Nemesis! Don’t revenge on us and describe the circuit in details, otherwise it’s not clear what elements are connected and how.

2006-12-12 08:32:34 · answer #3 · answered by Anonymous · 0 0

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