2006-12-12 05:57:56 · 6 answers · asked by lilballerina2004 1 in Science & Mathematics ➔ Chemistry
The Avogadro number (6.02*10^23) is the number of molecules in 1 mole of any substance.
So here you have: 8.50*10^22 / 6.02*10^23 = 0.1412 mol of NH3
1 mol of NH3 has a mass of (14+3) = 17g
so 0.1412 mol have a mass of 0.1412*17 = 2.4g
2006-12-12 06:01:38 · answer #1 · answered by claudeaf 3 · 1⤊ 0⤋
1 mol of NH3 contains 6.02x10^23 molecules if NH3, so the quantity of NH3 in moles is:
n = 8.05x10^22/6.02x10^23 = 0.134 mol
The molar mass of NH3 equals Mm = 17 g/mol, so:
m = n x Mm = 0.134 x 17 = 2.27 g
2006-12-12 06:05:14 · answer #2 · answered by Dimos F 4 · 0⤊ 0⤋
Nomber of moles 9.5*1022/6.02 10^23 =a million.613 10^(-20) moles of H2SO4 each and each and every mole of the acid has a million atom sulfur weight 32 g so mass of sulfur = a million.613*32 * 10^(-20 )= 5.16 10^(-19) g
2016-11-30 11:53:14 · answer #3 · answered by Anonymous · 0⤊ 0⤋
8.5x10^22 molecles x 1mol/6.02x10^23 molecules x17.04g of NH3/1mol of NH3=2.406g
17.04=molar mass of NH3
2006-12-12 06:21:48 · answer #4 · answered by lynn 2 · 0⤊ 0⤋
no of molecules=no of moles x 6.02 x 10^23(avogadro's no)
8.50 x 10^22=no of moles x 6.02 x 10^23
no of moles= 0.141196013
no of moles= total mass/mass of one mole
0.141196013= total mass/(14+(3 x 1)
total mass=2.400332226 grams
2006-12-12 06:24:45 · answer #5 · answered by Anonymous · 1⤊ 0⤋
6.023*10^23 molecules in a mole.
N = 14g / mole
H = 1.01g / mole
Figure it out.
2006-12-12 06:01:46 · answer #6 · answered by Blue_Lava_Chord 2 · 0⤊ 0⤋