A glass contains 0.25kg of water at 0.0.15kg of ice,also at 0 .is added to the water and it is noticed that after 11 min. all the ice hasw melted and all the water is now 15.Assuming that the thermal capacity of the glass may be ignored.
2006-12-12 05:52:57 · 2 answers · asked by candice m 1 in Science & Mathematics ➔ Physics
to melt 1g of ice you need 80 c
to melt 0.15kg = 150g of ice you need 150*80= 12000c
after this you have 0.15 +0.25kg =0.4kg =400g
to heat this from 0 to 15 you use
Q = m c (T(final)-T (initial)) = 400 *1 *15 = 6000c
total calories used 6000 +12000 = 18000calories
in Joules 18000 *4.18 = 75400 J
2006-12-12 06:31:49 · answer #1 · answered by maussy 7 · 0⤊ 0⤋
i do not get your question? do not you want an equation with the latent warmth in it?? and is not any longer that the first? yet someplace you want to easily accept (or locate) the quantity of warm temperature potential.
2016-10-18 04:20:49 · answer #2 · answered by dopico 4 · 0⤊ 0⤋