I need some serious help with this electricity Please!!?

Question

Ok I have a series-parallel circuit. I know that:
V(T) = 60 V
I(T) = 2 A
V(R2) = 30 V
R(3) = 30 Ohms

I have to find

V(R3)
R(2)
R(1)

Now I find V(R3) I think by doing the following:

V(R3) = V(T) - V(R2)
V(R3) = 60 V - 30 V
V(R3) = 30 V

If that is correct please... I beg you... Help me Find:

R(2)
R(1)

In that order. Please. I'm dying here! I have till tomarrow to do this... or i'm in TROUBLE... if you know what I mean. And If please don't leave mean or rude comments. If you don't know that's cool. But I'm in need of some serious help here. I would post a diagram, but I can't do that on here but I can tell you that there are 3 resistors. Imagine a square box. Now make a line down the middle. Now put in a resistor on the right side of the box. now put another on the bottom right side. now put one on the line that divides the box in half. now on the left side is the voltage. I hope this help... Ok I'm going to shut up now.

Thank you deeply for any help you can provide me.

Answer 1

Hey, remember me?

I think I finally get the picture you tried to draw.

Yes, that is correct for V(R3)= 30V

The voltage is equally split, so the value of resistance must be identical for R2 and R3 so R(2)= 30 ohm

For R(1), we now can figure the current through R2,R3
I=V/R
I=60V/60 ohm
I=1

I(R1) = I(t) - I(R2,R3)
I(R1) = 2 - 1
I(R1) = 1

Using ohm's law you then find the value of R1 = 60 ohm.

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Answer 2

I could help, but I cannot figure out your picture. For example you have 3 resistors. R1 is in series with R2 and R3 which are in parallel with each other. And the voltage is connected from one end of R1 to the opposite end of R2 and R3.

In any case it sounds like your analysis is correct so far. If V(R3) = 30V and R3 = 30Ohms then I(R3) = 1Amp, leaving the remainder for (I'm guessing here) R1 which also must be carrying 1Amp with 30Volts across it ( ie. 2Amps - 1Amp = 1Amp) So the R1 = 30 / 1 = 30 Ohms. Now, assuming that the total current is across R2 and the voltage across R2 is 30V, then R2 = 30/2 = 15 Ohms. I may have the R numbers wrong, but I suspect that the principles are correct.

Answer 3

You need to post more info concerning what resistor number corresponds to what postion. I am a little confused by this.

But from what you gave me I would start but setting the equivalent resistance = 30ohms. Equivalent resist of the circuit is equal to 1/((1/R1)+(1/(R2+R3))). This is assuming that R2 and R3 are in series and parallel to R1.

From Kirchoff's Laws we know that V(R1)=V(T) and V(T)=V(R1,R2) (this means the total voltage equals the sum of the series so V(T)=V(R1)+V(R2)).

I(T)=I(R1)+I(R1,R2) where I(R3)=I(R2) again from Kirchoff's Laws. So I(T)=I(R1)+I(R2) or I(T)=I(R1)+I(R3).

I think this should point you in the right direction.
Cause V(R3)=30 and V(R1)=60.
I(R3)=V(R3)/R3=1A=I(R2)
I(R1)=I(T)-I(R2)=2-1=1A
R2=V(R2)/I2=30/1=30ohms
R1=V(R1)/I(R1)=60/1=60ohms

Make sure you check this and I hope it helps. And remember I made assumptions about what resistor is placed where!!!

Answer 4

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Answer 5

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Answer 6

You just need to tell us which resistor is which..