A baseball diamond is a square.?

Question

The distance from first to second is 90ft. The catcher throws the ball from home to second. How far did he throw?

Answer 1

d = sqrt(90^ + 90^2)
d = sqrt(8100 + 8100)
d = sqrt(16200)
d = 127.28 ft

Answer 2

I'm sure the answer sought is SQRT(90^2+90^2)=127.28
"A catcher has to throw a distance of approximately 127'3" " (source 1)

However, the ball follows an arc (very close to a parabola) so that, the slower it is thrown, the longer the arc (a fast throw would not need to rise as high at the midway point).
Plus, the catcher must aim at a point a bit beyond second base, otherwise the ball could touch the ground (or the bag) just as it gets there, making it harder for the short-stop or second-baseman to catch it properly AND tag the runner.
"throw through the target, not to it" (from source 2).

A diamond is any four-sided flat figure where the four sides are equal in length. Thus, the square is a diamond. The square is a diamond where all four angles are 90 degrees.

Answer 3

Use the pythagorean theorem its a triangle and home to second is the long side of the triangle or C^2. A^2+B^2=C^2. Also if you need to know the distance from home to the mound is 60 ft 6 inches.

Answer 4

It's the square root of 90^2 + 90^2.

Answer 5

If he gets the man out at second base then he has thrown it far enough, fast enough and accurately enough. If he doesn't get the man out at second then it doesn't matter how far he threw it.

Answer 6

The length of the hypotenuse, Pythagoras.

Answer 7

127.28 feet

Answer 8

127.28... ft?