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when you invert the weight of something by 2 g's, do you just multipily the gravity(9.8) by 2?

2006-12-12 05:26:03 · 5 answers · asked by ndesrosiers27 1 in Science & Mathematics Physics

5 answers

yes, kind of

2006-12-12 05:30:54 · answer #1 · answered by Anonymous · 0 2

Your question is unclear, but this may help you understand the subject.

One 'G' is a unit of acceleration which is equivalent to the acceleration of gravity at the earth's surface. The acceleration of an object at rest is zero. The acceleration of an object in free fall near the earth's surface is one G but diminishes to zero as the object reaches terminal velocity.

Imagine a fighter jet carrying a one-pound weight on an in-line spring scale. Parked at the airport, the weight hangs down and the scale reads one pound. The plane takes off, points straight up, and accelerates at one G. The weight hangs down (toward the earth, and the rear of the plane) and reads 2 pounds, one from gravity and one from the one-G acceleration.

The plane shuts off its engines and points down. The plane is now in free-fall, and the scale reads zero. The force of gravity is exactly counteracted by the plane's downward acceleration of one G. Turn on the engines again and accelerate downward until the weight hangs up (away from the earth, toward the rear of the plane) and the scale reads one pound. The plane is accelerating toward the earth at 2G, one G due to gravity and one G due to engine thrust. To get the situation I think you are asking about, double the thrust of the engine. The scale will now read 2 pounds with the weight hanging up (away from earth).

2006-12-12 13:52:28 · answer #2 · answered by Frank N 7 · 0 0

Yes. Suppose a pilot in a fighter airplane pulls 6g. What does it mean? It means if his normal weight is 6okg, he will feel as if he is weighing 240kg. It becomes difficult for him even to lift his arm. It has serious implications on blood flow in the body. [Too much blood, or no blood to brain can dcapacitate him due to what is called redout or blackout.]

2006-12-12 13:37:33 · answer #3 · answered by openpsychy 6 · 0 1

1 g = F
F = m x a
F = m x gravity = m x 9.8ft/s/s

invert (reverse sign) by 2 gs;
-2 g = - 2F
F - 2F = (m x 9.8ft/s/s) - 2(m x 9.8ft/s/s)
-F = -1(m x 9.8ft/s/s)

2006-12-12 13:51:20 · answer #4 · answered by Anonymous · 0 0

First guy said it best. A simple "Yes" is all you need. You know what you are talking about.

2006-12-12 14:39:05 · answer #5 · answered by rawlings12345 4 · 0 1

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