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Light is a electromagnetic wave so, is it true for all electromagnetic wave?

2006-12-12 04:02:40 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

When anti-matter and matter interact, they do indeed produce photons. This happens in radioactive shields when high-energy gamma rays interact with a heavy nucleus (such as a lead atom) and form a pair of oppositely charged particles (an electron and a positron). The electrons and positrons are attracted to each other, collide, and disintegrate, producing photons. E=mc^2, and since electrons and positrons (each have the same mass, BTW) have a high enough mass, they produce photons with much, much more energy than light photons. In fact, they are gamma rays, which have a huge amount of energy compared to light photons. I can't think of any cases of matter and antimatter particles with small enough masses that their mutual annihilation produces photons in the visible light spectrum.

2006-12-12 04:15:20 · answer #1 · answered by Minnesota_Slinger 3 · 0 0

Matter - antimatter annihilations are extremely rare. Light (photons) is most commonly produced when an electron in orbit around the nucleus of an atom drops to a lower orbit with a lower energy level, and a photon is emitted whose energy is the difference between the two orbital energies.

2006-12-12 05:02:44 · answer #2 · answered by Frank N 7 · 0 0

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