team can lose ?

Question

A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?

(A) 7
(B) 6
(C) 5
(D) 4
(E) 3

Answer 1

First, they have played 17 + 3 = 20 games. Since this equals 2/3 of their total games, they will play 20 / (2/3) = 30 total games. 30 total games minus the 20 played already is 30 - 20 = 10 games left.

To win ¾ of 30 games, they have to win 30 * ¾ = 22½ games and to express that in whole games that satisfies the "at least ¾" one has to round up to 23. Having won 17 already, they must win 23 - 17 = 6 of their remaining games.

The answer needed though is how many of the rest they can lose and satisfy the problem. 10 remaining games minus the 6 they must win is 10 - 6 = 4 games they can lose.

So, 4 games can be lost and still win at least ¾ of their total games. That makes choice (D) the correct answer.

Answer 2

It is D : 4.

Since the team played 17+3=20 games which is also 2/3 of its games, you can conclude that 20=2/3*total games.
Thus, it played 30 games in total.

Now, to win at least 3/4*30 = 22.5 or 23 games it needs to win 23-17 = 6 more games at least. So there remains (30-20)-6 = 4 games to be lost in maximum.

So the greatest it can lose is 4.

Answer 3

The team has played 20 games. If that is 2/3 of its games, then:

Total games * 2/3 = 20 games
Total games * 2/3 * 3/2 = 3/2 * 20 games
Total games = 30 games
So, the team has 10 more games to play.

3/4 * 30 games = 22.5 games.
So, 22 games would be less than 3/4 and 23 games would be more than 3/4. So, the team has to win at least 23 games.

The team has won 17 games, so it has to win 6 more games out of the next 10.

10 - 6 = 4

So, the team can only lose 4 games.

Answer 4

The answer is (B) 6.
Why? They have played 2/3 of the games=20.That means there are 30 games totally .(2/3x=20.Therefore x=30.)
To win at least 3/4, they must win 23 games (3/4 of 30=22.5).
Since they have already won 17,they need to win 6 more (23-17)

Answer 5

total=3/2 *20=30 games
wins needed for 3/4 wins=22.5 say 23
already lost 3 gaes
they can afford to lose 7-3=another 4 games

Answer 6

Awnser is (D)

Reson: Team has already played 2/3 matches, which means 17 wins + 3 Losses will contribute equivalent to 2/3 of matches that means 17+3 = 20 is 2/3
So, total No. of matches will be 3/2*20=30
Now Max No. of matches team can loose is 1/4*30=7.5
as team has alrady lost 3 matches so balance remaining with them is = 7.5-3=4.5
that means Max 4

Answer 7

2/3x=20 therfore x=30 where x is total games to be played.now reaminig to be played is (30-20)=10. 3/4th of 30 is 22.5. thereby the greatest no.of games to lose is (7-3)=4