The lateral surface answer is 87,512 but that isn't what I get.
I take 930 divided by 4 to get the side of the base, than sq it. (54,056) Then 1/2 2325 x 148=68,820. Add the base to it and I get 122,876.
2006-12-12 03:15:55 · 3 answers · asked by Ann D 1 in Science & Mathematics ➔ Mathematics
Later surface S = 0.5(perimeter of base (p))*distance from middle point of a side to the vertex(d)
S = 0.5*(930)*sqrt[148^2 - [0.5*(930/4)]^2] =
42592.4199 m^2 approximately.
2006-12-12 03:29:57 · answer #1 · answered by mulla sadra 3 · 0⤊ 0⤋
Scrap my previous answer, it sucks. Two things about your answer:
1) You don't add the area of the base, by the way. It isn't part of the LATERAL surface.
2) The height of the pyramid isn't the same thing as the height of triangles that make up the lateral surface, because these triangles are slanted.
2006-12-12 11:21:54 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Okay I get (sqr((930/8)^2+148^2))*(930/8) * 4= 87511.55 approximately.
2006-12-12 13:29:17 · answer #3 · answered by yljacktt 5 · 0⤊ 0⤋