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At a certain diner, a hamburger and coleslaw cost $3.59, and a hamburger and french fries cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost?

(A) $0.30
(B) $0.45
(C) $0.60
(D) $0.75
(E) $0.90

2006-12-12 03:14:12 · 7 answers · asked by Amuthan A 1 in Science & Mathematics Mathematics

7 answers

let x=burger
let y=coleslaw
let z=french fries

x+y=3.49
x+z=4.40

since french fries cost twice as much as coleslaw..then z=2y

x+y=3.49
x+2y=4.40

subtract the two equations....
x+y-(x+2y)=3.49-4.40
x+y-x-2y=-0.81
-y=-0.81
y=0.81

since french fries =z=2y then
z=2y=2(0.81)=1.62

therefore, french fries costs $1.62

the answer is not on the list

2006-12-12 03:25:57 · answer #1 · answered by angel 2 · 0 0

(F) None of the above

$4.40 - $3.59 = $0.81

This is how much more the fires and burger are, right?

Well, fries are twice as much as slaw, so slaw must be $0.81, since fries are twice that, which is where the additional $0.81 comes from. So fries are $1.62, slaw is $0.81, and burger is $2.78.

Your answer is not in the list.

2006-12-12 11:23:35 · answer #2 · answered by jimvalentinojr 6 · 0 0

The fries are $1.62, if this is a homework question rather than something you made up, check your typing! You may've made a typo... or it's a trick question.

2006-12-12 11:30:05 · answer #3 · answered by Sheriam 7 · 0 0

None of the above .Answers given are wrong
The correct answer is 1.62

2006-12-12 14:58:33 · answer #4 · answered by mohanan p 1 · 0 0

h+c = $3.59
h+f = $4.40

Subtract the first from the second...
f - c = $4.40 - $3.59 = $0.81

Also, f =2c. You can take it from here...

2006-12-12 11:18:30 · answer #5 · answered by Anonymous · 0 0

h + c = 3.59
h + f = 4.40

f = 2 c

h + f = h + 2 c

(h + 2 c) - (h + c) = ?

2006-12-12 11:17:21 · answer #6 · answered by Raymond 7 · 0 0

f.) one heart attack

2006-12-12 11:38:49 · answer #7 · answered by kaaykes314 2 · 0 0

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