can you please help me to solve this equation? y=3x^2-24x+3?

Answer 1

y = 3x² - 24x + 3

Factor out the three's from the x's
y = 3(x² - 8x) + 3

Complete the square, and make sure you subtract what you have added
y = 3(x² - 8x + 16) + 3 - 48

Factor out the square trinomial
y = 3(x - 4)² - 45

Now, what do you want to solve?

^_^

Answer 2

For one thing, it's really not an equation to solve. If, however, you meant for

3x^2 - 24x + 3 = 0

Then your first step would be to recognize all coefficients are divisible by 3, so divide both sides by 3.

x^2 - 8x + 1 = 0

We could either use the quadratic formula or complete the square. I'm going to complete the square. I'm going to add "half squared" of -8 to both sides, which is 16.

x^2 - 8x + 16 + 1 = 16
(x - 4)^2 + 17 = 16
(x - 4)^2 = -1

Which has no solution.

Answer 3

Firstly, you cant solve an equation if it's not equals to zero (0).
Therefore, you can only factorise it, using squaring method.

y = 3x^2 - 24x + 3
= 3(x^2 -8x) + 3
= 3[(x-4)^2 - (4^2)] + 3
= 3(x-4)^2 - 48 + 3
= 3(x-4)^2 - 45

No other ways, dude.

Answer 4

To solve this there are 2 easy methods
1) Using the quadratic formula
Given the general form ax^2+bx+c

(-b +/- (b^2 - (4*a*c))^.5 )/2a

2) Or solve by inspection

to factorise a quadratic the numbers you chose have to multiply to the c and add to the b

Since this will not be a whole number answer ill use the quadratic formula ,
(-b +/- (b^2 - (4*a*c))^.5 )/2a
24 +/- 540^.5 / 6
x = (24 +/- 23.24 )/ 6

Answer 5

x+ y = 5 x = 5 - y x^2 + y^2 = 17 (5 -y)(5 -y) + y^2 = 17 25 - 5y - 5y + y^2 + y^2 = 17 2y^2 - 10y + 8 = 0 y^2 - 5y + 4 = 0 (y - a million)(y - 4) = 0 y = a million, 4 2x - y + 3 = 0 y = 2x + 3 y^2 - 5x^2 = 20 (2x + 3)(2x + 3) - 5x^2 = 20 4x^2 + 6x + 6x + 9 - 5x^2 = 20 -x^2 + 12x - 11 = 0 (x - a million)(x -11) = 0 x = a million, 11

Answer 6

y=3x^2-24x+3
use the quadratic formula
x = [ -b ± √(b^2 - 4ac) ] / 2a
a=3
b=-24
c=3

x = [ -(-24) ± √((-24)^2 - 4(3)(3)) ] / 2(3)
x = [ 24 ± √(576- 36) ] / 6
x = [24 ± √(540)] / 6
x = [24 ± √(36)√(15)] / 6
x = [24 ± 6√(15)] / 6
x = 4 ± √(15)

x = (4 +√15) & x = (4 - √15)

Answer 7

this is not an equation which can be solved.however we have factored it
y=3(x^2-8x+1)
=3(x^2-8x+16-16+1)
=3[(x-4)^2-(sq.rt15)^2]
=3(x-4+sq.rt15)(x4-sq.rt15)

Answer 8

this equation is a parabole equation.the solutions is points (x,y) and y=3(x^2-8x+1) with x,yreal.
the points (x,y)are on the parabole and are a infinity solutions.