2006-12-11 22:58:06 · 7 answers · asked by dimple 1 in Science & Mathematics ➔ Mathematics
X^2-X-X+1=0
X(X-1)-(X-1)=0
(X-1)(X-1)=0
(X-1)^2=0 THEN X=1
2006-12-11 23:04:15 · answer #1 · answered by grassu a 3 · 0⤊ 0⤋
x² - 2x +1 = 0
(x - 1)² = 0
x = 1
2006-12-12 11:52:40 · answer #2 · answered by Ranna Renni 2 · 0⤊ 0⤋
The highest power of x is 2 which implies two brackets
(x + ?)(x + ?)
Now, you need two numbers which add to make -2 and multiply to make 1. The only numbers which multiply to make 1 are (-1, -1) or (1,1). 1 + 1 = 2 and -1 + -1 = -2, so ? = -1
(x - 1)(x - 1) or (x - 1)^2
2006-12-12 07:01:47 · answer #3 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋
Rule to factor this function is:
y = ax^2 +bx + c = a(x-x1)(x-x2), where x1 and x2 are real roots.
In your case: find the roots .... x1= 1 and x2 = 1
Write the formula: x^2-2x+1 = 1(x-1)(x-1) = (x-1)^2
2006-12-12 07:04:50 · answer #4 · answered by vahucel 6 · 0⤊ 0⤋
It's a perfect square so = (x-1)^2
or (x-1)(x-1) if you prefer
2006-12-12 07:05:37 · answer #5 · answered by jimbell 6 · 0⤊ 0⤋
x² - 2x + 1
(x - 1)(x - 1)
(x - 1)(x - 1) = x² - x - x + 1 = x² - 2x + 1
- - - - - - - -s-
2006-12-12 07:28:56 · answer #6 · answered by SAMUEL D 7 · 0⤊ 0⤋
(x-1)(x-1)
therefore x=1
2006-12-12 07:01:44 · answer #7 · answered by dfysst 1 · 0⤊ 0⤋