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Find the y-intercept for -x+3y=15

2006-12-11 21:42:16 · 7 answers · asked by sugalums 1 in Science & Mathematics Mathematics

7 answers

the y-intercept occurs where x is equal to zero. so tell me what does y equal when x is zero...

2006-12-11 21:44:55 · answer #1 · answered by will i know people in heaven? 2 · 0 0

Rewrite as 3y = 15+x

y= (x/3)-5 for x=0 the intercept is 5

2006-12-11 21:46:08 · answer #2 · answered by maussy 7 · 0 0

The y-intercept for -x+3y=15 is when x=0:

-(0)+3y=15
3y=15
y=5

The y-intercept is P(0, 5)

2006-12-12 00:02:43 · answer #3 · answered by Luiz S 7 · 0 0

Find the y intercept

x = 0

- x + 3y = 15

0 + 3y = 15

3y/3 = 15/3

y = 5

The answer: When x = 0, the y intercept is 5

- - - - - - - - - -s-

2006-12-11 23:36:54 · answer #4 · answered by SAMUEL D 7 · 0 0

To find the y-intercept, x must be equal to zero.

Thus,
-x+3y=15
-0+3y=15
3y=15
y=15/3
y=5

So the y-intercept is 5. The coordinate of y-intercept is (0,5)

2006-12-11 21:47:12 · answer #5 · answered by Ong 2 · 0 0

-x+3y=15
3y = x+15
y = ⅓x + 5
For a linear equation which in the form of y=mx+c, m is the gradient and c is the y-intercept.
Hence, y-intercept = 5

====Alternative Method====

-x+3y=15
At y-axis, x=0
-0+3y=15
y=5
Hence, y-intercept = 5

2006-12-12 03:57:11 · answer #6 · answered by Ranna Renni 2 · 0 0

For y-intercept express the equation of the line in
y=mx+c format.
where 'm' is the slope and 'c' is the y-intercept.

3y=15+x
y=(x/3)+5

c=5 which is your y intercept that is (0,5)

2006-12-11 21:45:41 · answer #7 · answered by Som™ 6 · 0 0

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