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Could someone tell me how to find the slope of the line passing through the points (-8,-3) and (-2,2) thanks in advance to those of you that help.

2006-12-11 21:36:33 · 10 answers · asked by sugalums 1 in Science & Mathematics Mathematics

10 answers

The slope is [y2 - y1]/[x2 - x1]

= [2 - (-3)]/[(-2) - (-8)]

= 5/6

2006-12-11 21:40:24 · answer #1 · answered by Tom :: Athier than Thou 6 · 0 0

To find the slope of a line passing thru the points (-8,-3) and (-2,2):

m = (y-y1) / (x-x1)

m = (-3-2) / (-8-(-2)) = -5/-6

m = 5/6

2006-12-12 08:07:49 · answer #2 · answered by Luiz S 7 · 0 0

m=(y1-y2)/(x1-x2)
where
m is the slope
in point (-8,-3) the first refers to your x1 and the second to your y1
same in the point (-2,2) -2 will be set as x2 since this is your second x coordinate and 2 is your y2 with the same reason substituting the values to the given formula for slope will yield the equation

m=(-3-2)/(-8-(-2))
m=(-5)/(-6)
m=5/6 this is your slope

2006-12-12 05:54:12 · answer #3 · answered by arn_14 2 · 0 0

The formula for slope is [different in y]/[different in x] or δy/δx

For a line passing through the points (-8,-3) and (-2,2),
δy = 2-(-3) = 5
δx = -2-(-8) = 6

Hence, slope = δy/δx = 5/6

2006-12-12 12:00:25 · answer #4 · answered by Ranna Renni 2 · 0 0

Use gradient, m to determine the slope of the line. How? Use this formula.

m=(difference between two y-coordinate)/(difference between two x-coordinate)

Given (-8,-3) and (-2,2)
m=(2-(-3))/(-2-(-8))
=5/6

So, the slope/gradient of the line is 5/6.

2006-12-12 05:42:00 · answer #5 · answered by Ong 2 · 0 0

The formula for the gradient of a line passing thru two points is: m = (y2 - y1)/(x2 - x1). Therefore, in your particular case, the gradient m = [2 -(-3)]/[-2-(-8)] = 5/6. Expressed as an angle(theta) inclined to the x-axis, theta = arc tan(5/6) = 39.8 deg

2006-12-12 06:21:23 · answer #6 · answered by Paleologus 3 · 0 0

The formula for the slope of the line is m=(y2-y1)(x2-x1)

So in the given problem, y2=2; y1=-3; x2=-2; x1=-8

Hence slope m=(2-(-3))/(-2-(-8))
= 5/6

2006-12-12 06:24:59 · answer #7 · answered by Prince 3 · 0 0

Find the slope

Slope formula

m = y₂- y₁/x₂- x₁

Ordered Pair

(- 8, - 3)(- 2, 2)

m = -3 - 2/-8 - (- 2)

m = - 5/ -8 + 2

m = -5 / - 6

m = 5/6

- - - - - - - -s-

2006-12-12 07:44:03 · answer #8 · answered by SAMUEL D 7 · 0 0

The slope is 5/6, I think.

I got it by
(-2,2)
-
(-8,-3)
=(6,5)
=5/6

So you simply subtract them.

So you simply subtract them.

2006-12-12 06:23:45 · answer #9 · answered by ♫tweet75♫ 3 · 0 0

I would, but this tutorial does it better than I do and they even have pretty boxes, graphs, and examples that will help you really learn it.
http://www.wtamu.edu/academic/anns/mps/math/mathlab/beg_algebra/beg_alg_tut23_slope.htm

You'll have it in no time. Good luck on your work.

2006-12-12 05:41:51 · answer #10 · answered by bygoneincognito 2 · 0 0

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