Can anyone derive M=m/(1-v2/c2)^1/2?

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Can anyone derive M=m/(1-v2/c2)^1/2?

2006-12-11 21:01:21 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics

I need the equations and derivations which lead to this relativistic mass equation.

2006-12-11 21:12:21 · update #1

3 answers

Special relativity is fairly easy to derive from the single assumption that the speed of light is always observed to be 'c' no matter how the observer is moving - but a little too involved to do here. Try the Internet.

2006-12-11 21:19:29 · answer #1 · answered by hznfrst 6 · 1⤊ 1⤋

dM/dv= -2mv/c^2 (1-v^2/c^2) ^(-1/2))

2006-12-11 21:51:36 · answer #2 · answered by maussy 7 · 0⤊ 1⤋

pickles and cheese.

2006-12-11 21:08:47 · answer #3 · answered by Mike Hunt 2 · 0⤊ 1⤋