The * on the y means it is squared
2006-12-11 18:35:33 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
10y^2 + 15y -45=0
2y^2 +3y -9 =0
(2y-3)(y+3)=0
y= 3/2 or -3
2006-12-11 18:42:18 · answer #1 · answered by pigley 4 · 0⤊ 0⤋
10y² + 15y - 45 = 0
2y² + 3y - 9 = 0
(y + 3)(2y - 3) = 0
y = -3, 3/2
90 - 45 - 45 = 0
22.5 + 22.5 - 45 = 0
2006-12-12 02:42:24 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
10y* + 15y -45=0
2y*+3y-9=0
a=2, b=3,c=-9
d^2-4ac = 9+72
= 81
root of b^2-4ac = 9
y= (-3+9)/4, (-3-9)/4
= 6/4, -12/4
= 3/2,-3
2006-12-12 02:58:54 · answer #3 · answered by george t 2 · 0⤊ 0⤋
ok - what are the factors of 10
1*10 2*5
factors of 45
1*45 3*15 5*9
now our signs will be one + and one - since the 45 is a negative - BUT the larger number will be the positive one as the middle sign is +
so then we play with the number until we get a difference of 15 between them
(2y-3)(5y+15) = 0
2006-12-12 02:43:29 · answer #4 · answered by tom4bucs 7 · 0⤊ 0⤋
To simplify we can divide the whole equation by 5:
2y^2 + 3y - 9 = 0
Solving for y:
(2y-3)*(y+3) = 0
Then y =3/2 Or y = -3
2006-12-12 05:31:41 · answer #5 · answered by Noor O 2 · 0⤊ 0⤋
Divide throughout by 5,
then,
2y^2 + 3y - 9 = 0
2y^2 + 6y -3y - 9 = 0
2y(y+3) -3(y+3) = 0
(2y-3)(y+3) = 0
y= 3/2 OR y=-3
2006-12-12 03:06:22 · answer #6 · answered by yasiru89 6 · 0⤊ 0⤋
10y^2 + 15y - 45 = 0
5 (2x^2 + 3 - 9) = 0
5 (2x - 3) (x + 3) = 0
x=3/2, or x = -3
2006-12-12 05:27:57 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Factorizing 5(2y*+3y-9)=0
then 2y*+3y-9=0
so (2y-3)(y+3)=0
2 solutions: 1st=3/2, 2nd=-3
2006-12-12 02:49:14 · answer #8 · answered by rodh 1 · 0⤊ 0⤋
5(2y*+3y-9)=0
5(2y-3)(y+3)=0
y= 3/2 and -3
2006-12-12 02:40:02 · answer #9 · answered by leksa27 2 · 0⤊ 0⤋
y=1.5 or y= -3
2006-12-12 02:42:01 · answer #10 · answered by balaji s 1 · 0⤊ 0⤋