Need help Math review?

Question

It just says simplify
9-i
___

-4+5i

Answer 1

if the question you asked is 9-i/-4+5i
then u need to multiply and divide by the conjugate ie -4-5i and thus you can remove the i (square root of minus one) and just multiply the two terms in the numerator. the answer for this is:
-1-i

Answer 2

In abvanced maths, i is the square root of negative 1. It is only used at university level and is multiplied by itself so disappears. It cannot have a "real" value as you cannot get tha squareroot of a negative number.

Solution? 9 - i = 9 - i

and -4 + 5i = -4 + 5i

Answer 3

9-i = 9 - (-1)^(1/2)
-4+5i = -4 +5*(-1)^(1/2)

[9-(-1)^(1/2) ]/ [-4 +5*(-1)^(1/2)]
=[9-(-1)^(1/2) ]*[-4 -5*(-1)^(1/2)]/ [[-4 +5*(-1)^(1/2)]*[-4 +5*(-1)^(1/2)]]
(multiplied both sides by [-4 +5*(-1)^(1/2)] to get rid of the radical in the denominator.)

then you factor it out.

You'll get 16 + 25 * -1 or -9 for the denominator. You can do the top part yourself.

Answer 4

{(9 - i) / (-4 +5i)} x (-4 + 5i)

=(9 - i)(-4 + 5i)

=-5i^2 + 4i + 45i - 36
As i is sr rt of neg one and gathering like terms

= 49i - 41

Answer 5

(9-i)+(-13+6i)=(-4+5i)

Answer 6

You should do your own howework, Im not sure about the answer

Justin