how many atoms of AL are in 2.75 mol of AL?

5 ⤊

2006-12-11 17:38:40 · 6 answers · asked by muscular 1 in Science & Mathematics ➔ Chemistry

1.66 * 10^25

2006-12-11 17:40:30 · answer #1 · answered by ibrar 4 · 3⤊ 0⤋

1 mol = 6.02 x 10^23 atoms

2006-12-12 01:40:45 · answer #2 · answered by 12 November 3 · 0⤊ 0⤋

no of atoms
= avogrado constant*no of mol
= 6.02*10^23 * 2.75
=16.555*10^23
=1.66*10^24 (3 sig fig) :)

2006-12-12 01:49:51 · answer #3 · answered by pigley 4 · 1⤊ 0⤋

1.6555 times 10^24

2006-12-12 01:48:29 · answer #4 · answered by Anonymous · 0⤊ 0⤋

2.75*6.023*10^23=16.56*10^23=1.656*10^24

2006-12-12 01:40:54 · answer #5 · answered by yupchagee 7 · 1⤊ 0⤋

(2.75)*(6.023*10^23)=1.6*10^24

2006-12-12 02:48:55 · answer #6 · answered by shash 1 · 0⤊ 0⤋